Integrand size = 36, antiderivative size = 172 \[ \int \cos ^2(e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{3/2} \, dx=\frac {64 c^2 \cos (e+f x) (a+a \sin (e+f x))^{1+m}}{a f (7+2 m) \left (15+16 m+4 m^2\right ) \sqrt {c-c \sin (e+f x)}}+\frac {16 c \cos (e+f x) (a+a \sin (e+f x))^{1+m} \sqrt {c-c \sin (e+f x)}}{a f \left (35+24 m+4 m^2\right )}+\frac {2 \cos (e+f x) (a+a \sin (e+f x))^{1+m} (c-c \sin (e+f x))^{3/2}}{a f (7+2 m)} \]
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Time = 0.34 (sec) , antiderivative size = 172, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {2920, 2819, 2817} \[ \int \cos ^2(e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{3/2} \, dx=\frac {64 c^2 \cos (e+f x) (a \sin (e+f x)+a)^{m+1}}{a f (2 m+7) \left (4 m^2+16 m+15\right ) \sqrt {c-c \sin (e+f x)}}+\frac {16 c \cos (e+f x) \sqrt {c-c \sin (e+f x)} (a \sin (e+f x)+a)^{m+1}}{a f \left (4 m^2+24 m+35\right )}+\frac {2 \cos (e+f x) (c-c \sin (e+f x))^{3/2} (a \sin (e+f x)+a)^{m+1}}{a f (2 m+7)} \]
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Rule 2817
Rule 2819
Rule 2920
Rubi steps \begin{align*} \text {integral}& = \frac {\int (a+a \sin (e+f x))^{1+m} (c-c \sin (e+f x))^{5/2} \, dx}{a c} \\ & = \frac {2 \cos (e+f x) (a+a \sin (e+f x))^{1+m} (c-c \sin (e+f x))^{3/2}}{a f (7+2 m)}+\frac {8 \int (a+a \sin (e+f x))^{1+m} (c-c \sin (e+f x))^{3/2} \, dx}{a (7+2 m)} \\ & = \frac {16 c \cos (e+f x) (a+a \sin (e+f x))^{1+m} \sqrt {c-c \sin (e+f x)}}{a f \left (35+24 m+4 m^2\right )}+\frac {2 \cos (e+f x) (a+a \sin (e+f x))^{1+m} (c-c \sin (e+f x))^{3/2}}{a f (7+2 m)}+\frac {(32 c) \int (a+a \sin (e+f x))^{1+m} \sqrt {c-c \sin (e+f x)} \, dx}{a \left (35+24 m+4 m^2\right )} \\ & = \frac {64 c^2 \cos (e+f x) (a+a \sin (e+f x))^{1+m}}{a f (3+2 m) \left (35+24 m+4 m^2\right ) \sqrt {c-c \sin (e+f x)}}+\frac {16 c \cos (e+f x) (a+a \sin (e+f x))^{1+m} \sqrt {c-c \sin (e+f x)}}{a f \left (35+24 m+4 m^2\right )}+\frac {2 \cos (e+f x) (a+a \sin (e+f x))^{1+m} (c-c \sin (e+f x))^{3/2}}{a f (7+2 m)} \\ \end{align*}
Time = 8.72 (sec) , antiderivative size = 149, normalized size of antiderivative = 0.87 \[ \int \cos ^2(e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{3/2} \, dx=-\frac {c \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )^3 (a (1+\sin (e+f x)))^m \sqrt {c-c \sin (e+f x)} \left (-157-80 m-12 m^2+\left (15+16 m+4 m^2\right ) \cos (2 (e+f x))+4 \left (27+24 m+4 m^2\right ) \sin (e+f x)\right )}{f (3+2 m) (5+2 m) (7+2 m) \left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right )} \]
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\[\int \left (\cos ^{2}\left (f x +e \right )\right ) \left (a +a \sin \left (f x +e \right )\right )^{m} \left (c -c \sin \left (f x +e \right )\right )^{\frac {3}{2}}d x\]
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none
Time = 0.31 (sec) , antiderivative size = 243, normalized size of antiderivative = 1.41 \[ \int \cos ^2(e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{3/2} \, dx=\frac {2 \, {\left ({\left (4 \, c m^{2} + 16 \, c m + 15 \, c\right )} \cos \left (f x + e\right )^{4} + {\left (4 \, c m^{2} + 32 \, c m + 39 \, c\right )} \cos \left (f x + e\right )^{3} + 8 \, {\left (2 \, c m - c\right )} \cos \left (f x + e\right )^{2} + 32 \, c \cos \left (f x + e\right ) - {\left ({\left (4 \, c m^{2} + 16 \, c m + 15 \, c\right )} \cos \left (f x + e\right )^{3} - 8 \, {\left (2 \, c m + 3 \, c\right )} \cos \left (f x + e\right )^{2} - 32 \, c \cos \left (f x + e\right ) - 64 \, c\right )} \sin \left (f x + e\right ) + 64 \, c\right )} \sqrt {-c \sin \left (f x + e\right ) + c} {\left (a \sin \left (f x + e\right ) + a\right )}^{m}}{8 \, f m^{3} + 60 \, f m^{2} + 142 \, f m + {\left (8 \, f m^{3} + 60 \, f m^{2} + 142 \, f m + 105 \, f\right )} \cos \left (f x + e\right ) - {\left (8 \, f m^{3} + 60 \, f m^{2} + 142 \, f m + 105 \, f\right )} \sin \left (f x + e\right ) + 105 \, f} \]
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Timed out. \[ \int \cos ^2(e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{3/2} \, dx=\text {Timed out} \]
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Leaf count of result is larger than twice the leaf count of optimal. 423 vs. \(2 (164) = 328\).
Time = 0.48 (sec) , antiderivative size = 423, normalized size of antiderivative = 2.46 \[ \int \cos ^2(e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{3/2} \, dx=-\frac {2 \, {\left ({\left (4 \, m^{2} + 32 \, m + 71\right )} a^{m} c^{\frac {3}{2}} - \frac {{\left (4 \, m^{2} - 105\right )} a^{m} c^{\frac {3}{2}} \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} - \frac {{\left (12 \, m^{2} + 64 \, m - 91\right )} a^{m} c^{\frac {3}{2}} \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} + \frac {{\left (12 \, m^{2} + 32 \, m + 245\right )} a^{m} c^{\frac {3}{2}} \sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}} + \frac {{\left (12 \, m^{2} + 32 \, m + 245\right )} a^{m} c^{\frac {3}{2}} \sin \left (f x + e\right )^{4}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{4}} - \frac {{\left (12 \, m^{2} + 64 \, m - 91\right )} a^{m} c^{\frac {3}{2}} \sin \left (f x + e\right )^{5}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{5}} - \frac {{\left (4 \, m^{2} - 105\right )} a^{m} c^{\frac {3}{2}} \sin \left (f x + e\right )^{6}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{6}} + \frac {{\left (4 \, m^{2} + 32 \, m + 71\right )} a^{m} c^{\frac {3}{2}} \sin \left (f x + e\right )^{7}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{7}}\right )} e^{\left (2 \, m \log \left (\frac {\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + 1\right ) - m \log \left (\frac {\sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} + 1\right )\right )}}{{\left (8 \, m^{3} + 60 \, m^{2} + 142 \, m + \frac {2 \, {\left (8 \, m^{3} + 60 \, m^{2} + 142 \, m + 105\right )} \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} + \frac {{\left (8 \, m^{3} + 60 \, m^{2} + 142 \, m + 105\right )} \sin \left (f x + e\right )^{4}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{4}} + 105\right )} f {\left (\frac {\sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} + 1\right )}^{\frac {3}{2}}} \]
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\[ \int \cos ^2(e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{3/2} \, dx=\int { {\left (-c \sin \left (f x + e\right ) + c\right )}^{\frac {3}{2}} {\left (a \sin \left (f x + e\right ) + a\right )}^{m} \cos \left (f x + e\right )^{2} \,d x } \]
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Time = 15.35 (sec) , antiderivative size = 528, normalized size of antiderivative = 3.07 \[ \int \cos ^2(e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{3/2} \, dx=-\frac {\sqrt {c-c\,\sin \left (e+f\,x\right )}\,\left (\frac {c\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^m\,\left (m^2\,4{}\mathrm {i}+m\,16{}\mathrm {i}+15{}\mathrm {i}\right )}{4\,f\,\left (8\,m^3+60\,m^2+142\,m+105\right )}-\frac {c\,{\mathrm {e}}^{e\,7{}\mathrm {i}+f\,x\,7{}\mathrm {i}}\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^m\,\left (4\,m^2+16\,m+15\right )}{4\,f\,\left (8\,m^3+60\,m^2+142\,m+105\right )}-\frac {c\,{\mathrm {e}}^{e\,1{}\mathrm {i}+f\,x\,1{}\mathrm {i}}\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^m\,\left (4\,m^2+48\,m+63\right )}{4\,f\,\left (8\,m^3+60\,m^2+142\,m+105\right )}-\frac {c\,{\mathrm {e}}^{e\,5{}\mathrm {i}+f\,x\,5{}\mathrm {i}}\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^m\,\left (12\,m^2+80\,m-35\right )}{4\,f\,\left (8\,m^3+60\,m^2+142\,m+105\right )}+\frac {c\,{\mathrm {e}}^{e\,6{}\mathrm {i}+f\,x\,6{}\mathrm {i}}\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^m\,\left (m^2\,4{}\mathrm {i}+m\,48{}\mathrm {i}+63{}\mathrm {i}\right )}{4\,f\,\left (8\,m^3+60\,m^2+142\,m+105\right )}+\frac {c\,{\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^m\,\left (m^2\,12{}\mathrm {i}+m\,80{}\mathrm {i}-35{}\mathrm {i}\right )}{4\,f\,\left (8\,m^3+60\,m^2+142\,m+105\right )}-\frac {c\,{\mathrm {e}}^{e\,3{}\mathrm {i}+f\,x\,3{}\mathrm {i}}\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^m\,\left (12\,m^2+112\,m+525\right )}{4\,f\,\left (8\,m^3+60\,m^2+142\,m+105\right )}+\frac {c\,{\mathrm {e}}^{e\,4{}\mathrm {i}+f\,x\,4{}\mathrm {i}}\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^m\,\left (m^2\,12{}\mathrm {i}+m\,112{}\mathrm {i}+525{}\mathrm {i}\right )}{4\,f\,\left (8\,m^3+60\,m^2+142\,m+105\right )}\right )}{{\mathrm {e}}^{e\,4{}\mathrm {i}+f\,x\,4{}\mathrm {i}}-\frac {{\mathrm {e}}^{e\,3{}\mathrm {i}+f\,x\,3{}\mathrm {i}}\,\left (m^3\,8{}\mathrm {i}+m^2\,60{}\mathrm {i}+m\,142{}\mathrm {i}+105{}\mathrm {i}\right )}{8\,m^3+60\,m^2+142\,m+105}} \]
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